5x^2+1=4x-7

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Solution for 5x^2+1=4x-7 equation: 



5x^2+1=4x-7

We move all terms to the left:

5x^2+1-(4x-7)=0

We get rid of parentheses

5x^2-4x+7+1=0

We add all the numbers together, and all the variables

5x^2-4x+8=0

a = 5; b = -4; c = +8;
Δ = b2-4ac
Δ = -42-4·5·8
Δ = -144
Delta is less than zero, so there is no solution for the equation

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